Q-1      A stone dropped from on Aeroplane in an example of
            (a) Projectile
            (b) Range
            (c) Momentum
            (d) None
Q-2      y = kx2 is eq. of
            (a) Parabola
            (b) Ellipse
            (c) Hyperbola
            (d) None
Q-3      What is the path followed by projectile ?
            (a) Elliptical
            (b) Parabolic
            (c) Hyperbolic
            (d) None
Q-4      At q = 900, the value of R is,     Here R in Horizontal Range
(a)    1
(b)   0
(c)    2
(d)   3
Q-5      Sin (1800 – 3x) =?
            (a) Sin 2x
            (b) Sin 3x
            (c) Sin 4x
            (d) – Sin 3x
Q-6      When angle is 900, then value of time of flight is
            (a) 2a/g
            (b) 2b/g
            (c) 2u/g
            (d) None
Q-7      When a body slide from the inclined blame the value of acceleration is
            (a) g
            (b) Sin Ө
            (c) – g sin Ө
            (d) 0
Q-8      When a particle is projected from earth with velocity V0, then what will be its horizontal components of velocity.
            (a) V0 Cos Ө
            (b) V0 Sin Ө
            (c) V Cos Ө
            (d) None
Q-9      What is max. horizontal Range?
            (a) 4h
            (b) 5h
            (c) 9h
            (d) 10h
Q-10    Path followed by the projectile during it flight is ------
            (a) Trajectory
            (b) Horizontal Range
            (c) Momentum
            (d) None
Q-11    At What pt. in its path does a stone have zero speed?
            (a) At ground
            (b) At highest pt.
            (c) a & b
            (d) None
Q-12    At which angle a stone should be projected, so that it have max. horizontal Range
            (a) 600
            (b) 900
            (c) 450
            (d) None
Q-13    What is unit of Ө?
            (a) Radian       
            (b) Steradian
            (c) Rods-1
            (d) None
Q-14    In w = Ө/t, w is
            (a) Angular Displacement
            (b) Angular Speed
            (c) Time
            (d) None
Q-15    In circular motion the relation S = V0t can be written on
            (a) Ө = V0t      
            (b) Ө0 = Vt
            (c) Ө = w0t
            (d) None
Q-16    What is unit of angular acceleration.
            (a) Radian s-2
            (b) Radian s-3
            (c) Radian s-4
            (d) None
Q-17    What happen to angular acceleration if velocity is constant?
            (a) 0
            (b) 1
            (c) 2
            (d) 9
Q-18    In circular motion, V = V0 + at can be written as?
            (a) w = w2 + at            
(b) w = w0 + at
(c) w2 = w + at
(d) None
Q-19    T = 1/ ?
            (a) n
            (b) n2
            (c) n3
            (d) None
Q-20    Angular velocity is 
            (a) Axial vector
            (b) Rotational vector
            (c) Co-initial vector
            (d) None
Q-21    In Ө = l/r, l is
            (a) Radius
            (b) Arc
            (c) Angle
            (d) None
Q-22    Lt        Δy/Δt  =?
Δt ®0    
(a) dy/dt          
(b)   d2y/dt2
(c)    Δy/Δt
(d)   None
Q-23    When V = 1205 rpm. Here rpm stands for
            (a) Round per minute
            (b) Revolution per minute
            (c) Revolver per minute
            (d) None
Q-24    A stone is thrown vertically upward with velocity 10ms-1 which make an angle of 600 with horizontal, find Time of flight.
            (a) Ö3
            (b) Ö5
            (c) Ö41
            (d) Ö92
Q-25    The fly wheel of a generator makes 360 revolution in one minute. Find its angular velocity.         
            (a) 130π rad S-1
            (b) 120 π rad S-1
            (c) 125 π rad S-1
            (d) None
Answers:
1(a) Projectile
2(a) Parabola
3(b) Parabolic
4(b) 0
5(b) Sin 3x
6(c) 2u/g
7(b) Sin Ө
8(a) V0 Cos Ө
9(a) 4h
10(a) Trajectory
11(b) At highest pt.
12(c) 450
13(a) Radian
14(b) Angular Speed
15(c) Ө = w0t
16(a) Radian S-2
17(a) 0
18(b) w = w0 + at
19(a) V
20(a) Axial vector
21(b) Arc
22(a) dy/dt
23(b) Revolution per minute
24(a) Ö3
25(b) 120 π rad S-1
Reason
24                Here we use
T = 2V0 Sin d /g
2(10) Sin 600 / 9.8
2(10) Ö3/9.8 = 10 Ö3/9.8  = 5 Ö3/4.9
25                V = 360 revolution per minute
= 360/60 = 60 rotation per second
Since W = 2 π V = 2π(60) = 120 π red /S
Saturday, March 28, 2009
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